OH- (aq) + HCO3- (aq) --- H2O (l) + CO32-(aq) If OH is considered base 1, the right conjugates are..

The right conjugate of is

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

For the given chemical equation:

Here, is gaining a proton, thus it is considered as a brønsted-lowry base and after gaining a proton, it forms which is a conjugate acid.

Thus the right conjugate of is

answer: mercury

explanation:

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.