What is the molality of a solution made by dissolving 0.0816 moles of C6H1206 into 150.0 g of water?

m = 0.544 moles/kg

Explanation:

To do this, we need to use the expression for molality of a solution which is:

m = n / kg water

Where:

n: moles of solute

m: molality of solution

In this case, we have the moles of the solute, which is the C6H12O6 and the grams of water, and these grams would have to be turn into kg. Let's do this first:

kg of water = 150 g * 1 kg / 1000 g = 0.150 kg of water.

Now, replacing in the above expression of molality, we can calculate the molality of the solution:

m = 0.0816 / 0.150

the law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products. because atoms are only rearranged in a chemical reaction, there must be the same number of sodium atoms and chlorine atoms in both the reactants and products

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