Problem PageQuestion Aqueous hydrochloric acid HCl will react with solid sodium hydroxide NaOH to produce aqueous sodium chloride NaCl and liquid water H2O. Suppose 3.3 g of hydrochloric acid is mixed with 5.00 g of sodium hydroxide. Calculate the maximum mass of sodium chloride that could be produced by the chemical reaction. Round your answer to 2 significant digits.

Mass of Nacl = 4.92 gram (Approx)

Explanation:

Given:

Hydrochloric acid = 3.3 g

Sodium hydroxide = 5 g

Computation:

Hcl + NaoH ⇒ Nacl + H₂O

Number of mole of Hcl = 3.3 / 36.46 = 0.0905 moles

Number of mole of NaoH = 5 / 40 = 0.125 moles

We, know that number of moles in Hcl is less then number of mole in NaoH

So,

Number of mole of Hcl = Number of mole of Nacl

So,

Mass of Nacl = Number of mole of Nacl × Molar mass of Nacl

Mass of Nacl = 0.0905 × 54.4

Mass of Nacl = 4.92 gram (Approx)

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