If 200. g of water at 20°C absorbs 41 840 J of energy, what will its final temperature be? (Specific Heat of water is 4.184 J/g*C)

The final temperature will be

Explanation:

To calculate the specific heat of substance during the reaction.

where,

q = heat absorbed =41840 J

c = specific heat =

m = mass of water  = 200 g

= final temperature =?

= initial temperature =

Now put all the given values in the above formula, we get:

Thus the final temperature will be