Using the following balanced chemical equation 8 H2 + S8à 8 H2S. Determine the mass of the product (molar mass = 34.08g/mol) if you start with 1.35 g of hydrogen and 6.86 g of S8 (Molar mass = 256.5 g/mole).

7.29 g of will be produced from the given masses of both reactants.

Explanation:

To calculate the moles :

According to stoichiometry :

1 mole of require = 8 moles of

Thus 0.0267 moles of will require=  of

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

As 1 mole of give = 8 moles of

Thus 0.0267 moles of give =  of

Mass of

Thus 7.29 g of will be produced from the given masses of both reactants.

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