Ill give the brainliest answer to whoever helps me with this equation

The percent yield for the is, 86.7 %

Explanation : Given,

Moles of = 2.36 mol

Moles of = 6.14 mol

First we have to calculate the moles of

The balanced chemical equation is:

From the reaction, we conclude that

As, 2 moles of react to give 6 moles of

So, 2.36 moles of react to give mole of

Now we have to calculate the percent yield for the .

Experimental yield = 6.14 moles

Theoretical yield = 7.08 moles

Now put all the given values in this formula, we get:

Therefore, the percent yield for the is, 86.7 %

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