You’re trying to remove dissolved iron from a solution. The theoretical yield for a reaction between sodium sulfide and iron(III) bromide is 0.721 kilogram of solid iron(II) sulfide. When you carried out the reaction, you got 530.0 grams. What is the percent yield? FREEBE HAVENT SEEN THIS QUESTION YET

ANSWER!!!
The percent yield of the reaction is 73.5%

73.5%

Explanation:

Step 1:

Data obtained from the question.

Theoretical yield = 0.721Kg

Actual yield = 530g

Percentage yield =..?

Step 2:

Conversion of 0.721Kg to grams. This is illustrated below:

1Kg = 1000g

Therefore, 0.721Kg = 0.721 x 1000 = 721g

Step 3:

Determination of the percentage yield.

The percentage yield can be obtained by using the following formula:

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield = 530/721 x 100

Percentage yield = 73.5%

Therefore, the percentage yield is 73.5%

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.