Answers: 2
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](/tpl/images/0679/0203/09236.png)
.................(1)
= mass of iron = 360 g
= mass of water = 750 g
= final temperature = 
= temperature of iron = ?
= temperature of water = 
= specific heat of iron = 
= specific heat of water= 
![-360\times 0.450\times (46.7-x)=[750\times 4.184\times (46.7-22.5)]](/tpl/images/0679/0203/039f8.png)
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A 360. g iron rod is placed into 750.0 g of water at 22.5°C. The water temperature rises to 46.7°C....
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