An aluminum can weighing 10 g absorbs 106.8 J of heat and warms by 12oC. What is the specific heat of the aluminum can?

The specific heat of the aluminium can is 0.89 J/g°C

Explanation:

Step 1: Data given

Mass of the aluminium can = 10.0 grams

The amount of energy absorbed = 106.8 J

The temperature rises 12.0 °C

Step 2: Calculate the specific heat of the aluminium can

Q = m*c* ΔT

⇒with Q = the heat absorbed = 106.8 J

⇒with m = the mass of the aluminium can = 10.0 grams

⇒with c = the specific heat of the aluminium can = TO BE DETERMINED

⇒with ΔT = the rise of the temperature = 1.0°C

106.8 J = 10.0 grams * C * 12.0 °C

C = 106.8 J / (10.0 grams * 12.0 °C)

C = 0.89 J/g°C

The specific heat of the aluminium can is 0.89 J/g°C

c) should be the answer.