Calculate the theoretical yield and percent yield for this experiment

A. Theoretical yield of KCl is 36.49g

B. Percentage yield of KCl is 90.4%

Explanation:

The balanced equation for the reaction is given below:

2KCLO3 —> 2KCl + 3O2

Next, we shall determine the mass KClO3 that decomposed and the mass KCl produce from the balanced equation. This is illustrated below:

Molar mass of KClO3 = 39 + 35.5 + (16x3) = 122.5g/mol

Mass of KClO3 from the balanced equation = 2 x 122.5 = 245g

Molar mass of KCl = 39 + 35.5 = 74.5g/mol

Mass of KCl from the balanced equation = 2 x 74.5 = 149g.

From the balanced equation above,

245g of KClO3 decomposed to produce 149g of KCl.

A. Determination of the theoretical yield of KCl. This is illustrated below:

From the balanced equation above,

245g of KClO3 decomposed to produce 149g of KCl.

Therefore, 60g of KClO3 will decompose to produce = (60 x 149)/245 = 36.49g of KCl.

Therefore, the theoretical yield of KCl is 36.49g

B. Determination of the percentage yield of KCl. This can be obtaine as follow:

Actual yield = 33g

Theoretical yield = 36.49g

Percentage yield =..?

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield = 33/36.49 x 100

Percentage yield of KCl = 90.4%

a) the particles of the chair are strongly held together.

water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.