Calculate the empirical formula of a compound with the following percentage composition: 31,8% K; 29,0% C1; 39,2% O
The empirical formula of ethane is CH. Its molar mass is 30 g. mol-

The empirical formula for this compound is thus CH2.

Explanation:

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.