Determine the total kilojoules in two tablespoons of crunchy peanut butter that contains 6 g of carbohydrate, 11 g of fat, and 9 g of protein.

The number of kilojoules in two table spoons of crunchy peanut butter obtained by adding the amount of kilojoules in each food type is 673kJ

From the table given ; the amount of kilojoules per gram of each food type is :

I gram of Carbonhydrate = 17 kJ

6 grams of Carbonhydrate = (6 × 17) = 102 kJ

I gram of Fat = 38 kJ

11 grams of Carbonhydrate = (11 × 38) = 418 kJ

I gram of Protein = 17 kJ

9 grams of Carbonhydrate = (9 × 17) = 153 kJ

Therefore, the total kilojoules present is (102 + 408 + 153)kJ = 673 kJ

Learn more :link

  665 kJ

Explanation:

We assume that carbohydrates and protein each have 4 kilocalories per gram, and that fat has 9 kilocalories per gram. Then the number of kilocalories in the peanut butter is ...

  4(6 +9) +9(11) = 159 . . . . kilocalories

Each kilocalorie translates to 4.184 kilojoules, so the total is ...

  (159 kCal)(4.184 kJ/kCal) = 665.256 kJ

2 Tbsp of crunchy peanut butter contains about 665 kJ of energy.

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.