When a solution of KOH is neutralized by hydrochloric acid, the solution gets hot.
Calculate the change in heat of the solution (in J).
Mass of combined solution = 45.0 g
Temperature change of the solution = 23.5 K
Specific heat capacity of the solution = 4.18 J/g. K
Give your answer to three significant figures.
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Explanation:

Temperature change of the solution = 23.5 K

Specific heat capacity of the solution = 4.18 J/g.K

Give your answer to three significant figures.

J

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as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

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