Chemistry, 30.05.2020 17:59 chicacrazy8338
To determine [H3O+] in 0.00250 M HNO2(aq)(Ka=4.5.×10−4), the first equation we would obtain in solving for x=[H3O+] isKa=[H3O+][NO2−][HNO2]=x20.00250−x Normally when x<5% Minitial, we solve this equation using the quadratic formula. This tutorial will lead you through an alternative method called successive approximations.
Now you will solve the same problem as above, but using the quadratic formula instead of iterations, to show that the same value of x is obtained either way. Using the quadratic equation to calculate [H3O+] in 0.00250 M HNO2, what are the values of a, b, c and x , where a, b, and c are the coefficients in the quadratic equation ax2+bx+c=0, and x is [H3O+]? Recall that Ka=4.5×10−4 .
Answers: 3
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In the cathode ray tube experiment, j. j. thomson passed an electric current through different gases inside a cathode ray tube in the presence of an electric field. in which two ways did this experiment change scientists’ understanding of the atom?
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Consider the following reactions. (note: (s) = solid, (l) = liquid, and (g) = gas.) mg(s) + ½o2(g) → mgo(s) + 146 kcal/mole h2(g) + ½o2(g) → h2o(g), δh = -57.82 kcal/mole what type of reaction is represented by the previous two examples?
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To determine [H3O+] in 0.00250 M HNO2(aq)(Ka=4.5.×10−4), the first equation we would obtain in solvi...
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