How many moles of NaOH is needed to neutralize 45.0ml of 0.30M H2SeO4?

0.027 mole of NaOH.

Explanation:

We'll begin by obtaining the number of mole H2SeO4 in 45mL of 0.30M H2SeO4

This is illustrated below:

Molarity of H2SeO4 = 0.3M

Volume of solution = 45mL = 45/1000 = 0.045L

Mole of H2SeO4 =...?

Mole = Molarity x Volume

Mole of H2SeO4 = 0.3 x 0.045

Mole of H2SeO4 = 0.0135 mole

Next, the balanced equation for the reaction. This is given below:

H2SeO4 + 2NaOH –> Na2SeO4 + 2H2O

From the balanced equation above,

1 mole of H2SeO4 required 2 moles of NaOH.

Therefore, 0.0135 mole of H2SeO4 will require = 0.0135 x 2 = 0.027 mole of NaOH.

Therefore, 0.027 mole of NaOH is needed for the reaction.

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