Two equal and opposite charges sperated by a doctor stance d experience an attractive qn attractive force f .Ir eaxh charge is doubled in magnitude what would be the new diatance between them so that the force remains the same

Well first of all I wanted to tell you that the wording of your question is very imprecise or precise, there are letters or terms that are poorly written.

Although I was able to interpret where you wanted to go, whenever two opposite charges attract each other they generate an attraction field, where the force vectors are linear and if the number of charges is doubled the force remains equal to half the initial distance

Explanation:

This means that the greater the load, the shorter the distance between them, if they are opposite. In the case that they were the same there would be forces of repulsion and it would be the opposite case, but it is not appropriate to explain that topic to you.

Therefore the intensity variables of the load and the distance between them are indirectly proportional because if one increases the other decreases and if one decreases the other increases.

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol