At standard temperature and pressure 1 mole of any gas has a volume of 22.4 liters of gas. If the 5 grams of baking soda reacted at standard temperature and pressure, what volume of gas would be produced?

1.33L of gas

Explanation:

1 mole of Baking soda (NaHCO₃) reacts with acetic acid producing 1 mole of CO₂, water and sodium acetate, thus:

NaHCO₃ + CH₃COOH → NaCH₃COO + H₂O + CO₂

5g of NaHCO₃ (Molar mass: 84g/mol) are:

5g × (1mol / 84g) = 0.0595 moles of NaHCO₃ that produce 0.0595 moles of CO₂ -Moles of gas-.

If 1 mole of gas occupies 22.4L, 0.0595 moles occupy:

0.0595 moles gas × (22.4L / mol) = 1.33L of gas

adding or remove a gaseous reactant or product changes the concentrations. if the concentration of reactant or product is increased, the system will shift away from the side in which concentration was increased (i.e. if the concentration of reactants is increased, the system will shift toward the products. if more products are added, the system will shift to form more reactants). conversely, if the concentration of reactant or product is decreased, the system will shift toward the side in which concentration was decreased (i.e. if reactants are removed, the system will shift to form more reactants. if the concentration of products is decreased, the equilibrium will shift toward the products).

explanation: