What concentration of HOCl (Ka = 3.5 × 10-8) has the same pH as that of 2.50 × 10-4 molar HNO3? (Hint: HNO3 is a strong acid.)

1.79 molar

Explanation:

[H+] = 2.5*10-4 M

HOCl = H+ + OCl -

Ka = [H+]*[OCl-]/[HOCl]

[H+] = [OCl-] = 2.5*10-4 M

C (HOCl) = [H+]*[OCl-]/Ka = (2.5*10-4)^2/(3.5*10^-8)

= 1.79 M.

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