What is the concentration of the silver ion in silver chromate, Ag₂CrO₄, if its solubility product constant (Kₛₚ) is 1.2 x 10⁻¹². Hint: write the equation first! *

2 points

1.4 x 10⁻⁵

1.1 x 10⁻⁹

1.6 x 10⁻¹²

2.4 x 10⁻¹²

Explanation:

Hello,

In this case, given the solubility product of silver chromate:

Now, the law of mass action excluding silver chromate as it is solid, turns out:

Thus, given the change due to the dissolution of silver chromate, we obtain:

Hence, we solve for :

Thus, the concentration of silver ions will be:

Best regards.

what does the table look like