What is the molarity of a solution of sulfuric acid if 49.0 mL of it are neutralized by a titration

of 68.4 mL of 0.333 M sodium hydroxide solution? (Round to the correct number of sig figs

and include your units!)

Explanation:

Hello,

In this case, since the reaction between sulfuric acid and sodium hydroxide is:

H2SO4+2NaOH⇒Na2SO4+2H2O

We find a 1:2 molar ratio between the acid and the base, for that reason, at neutralization we verify:

That in terms of concentration and volumes:

With it, we can compute the molarity of the acid solution:

Best regards.

1. the question asks the most appropriate, which seems to rule out "all of the above." your choice appears to be the correct one.

2. the protocol described is good for identifying correlation, but not cause and effect. for cause/effect, you need to devise a protocol that will assign the treatment (or not) to groups that have essentially the same "demographics" with respect to all the other variables. your choice regarding control group seems appropriate. random assignment of treatment (choice d) may be appropriate also. (i think you can argue that b and d are just different descriptions of the same method.)

3. d will randomize the birds, but may not guarantee there are 10 in each group. e will do both, so seems the better choice.

comment on question 2

based on the problem statement, it seems clear that confident, attentive drivers are more likely to use daytime running lights. so, the protocol might need to be devised in such a way that the lights would be turned on or off without the driver's knowledge. (an attentive driver will figure it out.) assigning a confident, attentive driver to a group required to drive without running lights might mess with his/her confidence and attentiveness. you don't want your experiment to do that. (nor do you want the experiment to subject a driver to greater risk of accident as a consequence of driving without running lights.) experiments involving human safety are always problematic.

i don't know people like to fight everywhere rip.