Cacl2+2AgNO3(aq)-> Ca(No3)2 (aq)+2AgCl (s) if 25.0mL of a 2.00 m CaCl2 solution is used for the reaction shown above how many miles of chloride ions were involved in the reaction? Moles

Explanation:

Hello,

In this case, given the 2.00 M solution, we can compute the moles of calcium chloride that reacted:

Then, since in one mole of calcium chloride, we find two moles of chloride ions (see subscript), we can compute the moles of chloride ions that were involved in the reaction as shown below:

Best regards.

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )

there are two significant figures.