Calvin is setting up a model of the solar system. He positions a cardboard sun at one end of a school hallway and Pluto at the other end, 20 m away.
Calvin knows that Pluto is 39.5 AU from the sun and Jupiter is 5.27 AU from the sun
In order to make his model scale, how many meters from the cardboard sun should Calvin place Jupiter? (record your answer to two decimal places or nearest hundredth)

  2.67 m

Explanation:

We can write the proportion several ways. One of them is ...

  (model to Jupiter)/(Jupiter distance) = (model to Pluto)/(Pluto distance)

  (model to Jupiter)/5.27 = 20 m/39.5 . . . . . fill in the numbers

  (model to Jupiter) = 20 m(5.27/39.5) ≈ 2.67 m

The model of Jupiter should be placed 2.67 meters from the sun.

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )