What is the pH of a solution of KOH with a hydroxide concentration of [OH⁻] = 1.10 x 10⁻⁴

Explanation:

As we know that

......eq (1)

we will calculate the pH of OH- and then we will calculate the pH of H+

So p[OH-]

Solving the right side of the equation, we get

p[OH-]

Now we know that

Substituting the value of pOH in the above equation, we get -

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