What mass of Gallium chloride would react with excess fluorine to produce 78.9 g of chlorine? Gallium fluoride is the other product. 2 GaCl3 + 3 F2 2 GaF3 + 3 Cl2

130.2 g

Explanation:

To calculate the moles :

According to stoichiometry :

3 moles of require  = 2 moles of

Thus 1.11 moles of will require=  of

Mass of

Thus 130.2 g of gallium chloride would react with excess fluorine to produce 78.9 g of chlorine

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