How many moles of barium hydroxide can be produced from the reaction of 4.234 moles of barium with 8.902 moles of water according to the following reaction? Ba + 2 H2O Ba(OH)2 + H2

Thus 4.234 moles of will be produced from the given masses of both reactants.

Explanation:

The balanced chemical reaction is :

According to stoichiometry :

1 mole of require =  2 moles of

Thus 4.234 moles of will require=  of

Thus is the limiting reagent as it limits the formation of product and is the excess reagent as it is present in more amount than required.

As 1 mole of give = 1 mole of

Thus 4.234 moles of will give =  of

Thus 4.234 moles of will be produced from the given masses of both reactants.

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3