Chemistry, 22.05.2020 21:57 shanicar33500

(6) A mixture of 40.0 g of oxygen and 40.0 g of helium has a total pressure of 0.900 atm.
What is the partial pressure of each gas?

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Answer from: erinmcdonaldr6860

The partial pressure of each gas are:

1. The partial pressure of oxygen is 0.1 atm.

2. The partial pressure of helium is 0.8 atm.

We'll begin by calculating the number of mole of each gas:

For Oxygen:

Mass = 40 g

Molar mass = 32 g/mol

Mole of Oxygen = ?

Mole = mass / molar mass

Mole of Oxygen = 40 / 32

Mole of Oxygen = 1.25 moleFor Helium:

Mass = 40 g

Molar mass = 4 g/mol

Mole of Helium = ?

Mole = mass / molar mass

Mole of Helium = 40 / 4

Mole of Helium = 10 molesNext, we shall determine the total of the gases in the mixture.

Mole of Oxygen = 1.25 mole

Mole of Helium = 10 moled

Total mole = 1.25 + 10

Total mole = 11.25 molesNext, we shall determine the mole fraction of oxygen

Mole of Oxygen = 1.25 mole

Total mole = 11.25 moles

Mole fraction of Oxygen =?

Mole fraction = mole / total mole

Mole fraction of Oxygen = 1.25 / 11.25

Mole fraction of Oxygen = 0.111

1. Determination of the partial pressure of oxygen

Mole fraction of Oxygen = 0.111

Total pressure = 0.9 atm

Partial pressure of Oxygen = ?

Partial pressure = mole fraction × total pressure

Partial pressure of Oxygen = 0.111 × 0.9

Partial pressure of Oxygen = 0.1 atm

2. Determination of the partial pressure of Helium

Partial pressure of Oxygen = 0.1 atm

Total pressure = 0.9 atm

Partial pressure of Helium =?

Partial pressure of Helium = Total pressure – Partial pressure of Oxygen

Partial pressure of Helium = 0.9 – 0.1

Partial pressure of Helium = 0.8 atm

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Answer from: ericamiller165p58e0p

Partial pressure of oxygen = 0.100 atm

Partial pressure of Helium = 0.800 atm

Explanation:

We will first find the number of moles of each gas

The molar mass of oxygen is grams per mole

The molar mass of helium is grams per mole

The number of moles of oxygen in the solution

$\frac{40}{32} \\1.25$

The number of moles of helium in the solution

The number of moles of oxygen in the solution

$\frac{40}{4}\\10$

Total number of moles in the solution is equal to

$10 + 1.25 \\11.25$

Partial pressure of oxygen

$\frac{1.25 }{11.25} * 0.900$ atm

= 0.100 atm

Partial pressure of Helium

$\frac{10 }{11.25} * 0.900$ atm

= 0.800 atm

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(6) A mixture of 40.0 g of oxygen and 40.0 g of helium has a total pressure of 0.900 atm.
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