What is the final temperature of 150.1 g of water (specific heat = 4.18 J/g･°C) at 24.2°C that absorbed 950. J of heat?
NEED ANSWER ASA

Final temperature = 25.71°C

Explanation:

By using formula Q=mcΔT

let's say x is final temperature

950 = 150.1 × 4.18 × ( x - 24.2 )

950 = 627.418 × ( x - 24.2)

950 = 627.418x - 15183.5156

627.418x - 15183.5156 = 950

627.418x = 950 + 15183.5156

627.418x = 16133.5156

x = 16133.5156 / 627.418

x = 25.71 °C

So...the final temperature is 25.71 °C

the answer to this question is 3.