Chemistry, 22.05.2020 05:04 bignutz29

1. A solution was made by dissolving 0.837g of Ba(OH)2 in 100 mL of solution. What is the pOH and pH of the solution?

2. What is the percentage ionization of 1.0M acetic acid? What is the pH of this solution?

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Answer from: ggperez68

1. pOH = 1.01 and the pH = 12.99.

2. a) %I = 0.417 %, b) pH = 2.34.

Explanation:

1. The pH of the dissolution of Ba(OH)₂ in water can be calculated using the following equation:

$pH = 14 - pOH = 14 - (-log[OH^{-}]) = 14 + log[OH^{-}]$

To find the pOH, first, we need to calculate the concentration (C) of Ba(OH)₂:

$C_{Ba(OH)_{2}} = \frac{\eta}{V} = \frac{m}{M*V}$

Where:

η: is the number of moles of Ba(OH)₂

V: is the volume of the solution = 100 ml = 0.100 L

M: is the molar mass of Ba(OH)₂ = 171.34 g/mol

m: is the mass of Ba(OH)₂ = 0.837 g

$C_{Ba(OH)_{2}} = \frac{m}{M*V} = \frac{0.837 g}{171.34 g/mol*0.100 L} = 0.049 mol/L$

Knowing that in 1 mol of Ba(OH)₂ we have two moles of OH⁻, the concentration of OH⁻ is:

$C_{OH^{-}} = \frac{2*\eta_{Ba(OH)_{2}}}{V} = 2*C_{Ba(OH)_{2}} = 2*0.049 mol/L = 0.098 mol/L$

Now, we can find the pOH and the pH of the solution:

$pOH = -log[OH^{-}] = -log(0.098) = 1.01$

pH = 14 - pOH = 14 - 1.01 = 12.99

2. a) The percentage of ionization (% I) of acetic acid can be calculated using the following equation:

$\% I = \frac{[H^{+}]_{eq}}{[HA]_{0}}*100$

We need to find the [H⁺] = [H₃O⁺] at the equilibrium:

CH₃COOH(aq) + H₂O(l) → CH₃COO⁻(aq) + H₃O⁺(aq)

1.0 - x x x

$Ka = \frac{[CH_{3}COO^{-}]*[H_{3}O^{+}]}{[CH_{3}COOH]}$

Ka: is the dissociation constant of acetic acid = 1.75x10⁻⁵

$1.75\cdot 10^{-5} = \frac{x^{2}}{1.0 - x}$

$1.75\cdot 10^{-5}(1.0 - x) - x^{2} = 0$ (1)

By solving equation (1) for x we have two solutions:

x₁ = -0.00417

x₂ = 0.00417 = [H₃O⁺] = [CH₃COO⁻]

We will take the positive value to find the percentage ionization:

$\% I = \frac{[H^{+}]_{eq}}{[HA]_{0}}*100 = \frac{0.00417 M}{1.0 M}*100 = 0.417 \%$

b) The pH of the solution is:

$pH = -log([H_{3}O^{+}]) = -log(0.00417) = 2.34$

I hope it helps you!

Answer from: Quest

definition

entropy is a measure of the randomness or the extent of disorder of a chemical process.

enthalpy is a measure of the heat change of a reaction occurring at a constant pressure.

measurement units:

entropy is measured in joule per kelvin (jk⁻¹) whereas enthalpy is measured in joule per mole (jmol⁻¹)

requirements:

entropy has no requirements or limits, and its change is measured by the division between the heat change of the chemical process and the temperature.

in contrast, enthalpy can only be related to the heat change of the reaction under standard conditions.

Answer from: Quest

може ли да зареждате повече информация, моля

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1. A solution was made by dissolving 0.837g of Ba(OH)2 in 100 mL of solution. What is the pOH and pH...

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