Consider the molecule below. Determine the hybridization at each of the 2 labeled carbons. There is HF with Cl single-bonded to the second (from left to right) carbon and CH3 single-bonded to the fourth carbon. The first and the third carbons both have H single-bonded. There is a double bond between the first and the second and between the third and the fourth carbons. The second carbon of the chain is labeled as 1 and the carbon of the CH3 group is labeled as 2. Consider the molecule below. Determine the hybridization at each of the 2 labeled carbons. There is HF with Cl single-bonded to the second (from left to right) carbon and CH3 single-bonded to the fourth carbon. The first and the third carbons both have H single-bonded. There is a double bond between the first and the second and between the third and the fourth carbons. The second carbon of the chain is labeled as 1 and the carbon of the CH3 group is labeled as 2. C1 = sp2, C2 = sp3d C1 = sp2, C2 = sp2 C1 = sp3d, C2 = sp3d2 C1 = sp3, C2 = sp2 C1 = sp2, C2 = sp3