Chemistry, 14.05.2020 16:57 lindsaymiklavic04

How many moles of carbon dioxide are produced when 4.00 L of propane are reacted at STP?
C3H8 + 5O2 —> 3CO2 + 4H2O

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Answer from: lovelife78

$\large \boxed{\text{0.528 mol}}$

Explanation:

We will need a balanced chemical equation with moles and volumes, so, let's gather all the information in one place.

C₃H₈ + 5O₂ ⟶ 3CO₂ + 4H₂O

V/L: 4.00

(a) Moles of C₃H₈

We can use the Ideal Gas Law:

pV = nRT

Data:

p = 1 bar

V = 4.00 L

T = 273.15 K

Calculation:

$\begin{array}{rcl}\\pV &=& nRT\\\text{1 bar}\times\text{4.00 L} & = & n \times 0.08314 \text{ bar}\cdot\text{L}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{ 273.15 K}\\4.00 & = & 22.71n \text{ mol}^{-1}\\n & = & \dfrac{4.00}{22.71 \text{ mol}^{-1}}\\\\& = & 0.1761 \text{ mol}\\\end{array}$

(b) Moles of CO₂

The molar ratio is 3 mol CO₂/1 mol C₃H₈.

$\text{Moles of CO}_{2} = \text{0.1761 mol C$_{3}$H}_{8} \times \dfrac{\text{3 mol CO}_{2}}{\text{1 mol C$_{3}$H}_{8}} = \textbf{0.528 mol CO}_{2}\\\\\text{The reaction produces $\large \boxed{\textbf{0.528 mol CO}_{2}}$}$

Answer from: Quest

wanahton purified a portion of water with 900 grams of contaminants. each hour, a third of the contaminants was filtered out.

let g(n) be the amount of contaminants (in grams) that remained by the beginning of the nth hour. g is a sequence, what kind of sequence is it, arithmetic or geometric? then, write an explicit formula for the sequence, g(n)=

wanahton purified a portion of water with 900 grams of contaminants. each hour, a third of the contaminants was filtered out.

explanation:

Answer from: Quest

It’s b. mass i searched it up

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How many moles of carbon dioxide are produced when 4.00 L of propane are reacted at STP?
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