How many liters of methane gas (ch4) need to be combusted to produce 12.4 liters of water vapor, if all measurements are taken at the same temperature and pressure? show all of the work used to solve this problem.

ch4 (g) + 2 o2 (g) > co2 (g) + 2 h2o (g)

The balanced chemical reaction is written as:

CH4 (g) + 2 O2 (g) > CO2 (g) + 2 H2O (g)

We are given the amount of water to be produced from the reaction. This amount will be used for the calculations. Calculations are as follows:

12.4 L H2O ( 1 mol / 22.4 L ) ( 1 mol CH4 / 2 mol H2O ) ( 22.4 L / 1 mol ) = 6.2 L CH4

Adozen is 1221/12 = 1.751.75 x 12 = 21therefore, 1.75 is the answer.