Chemistry, 06.05.2020 23:05 bellamore

H2 reacts with the halogens (X2) according to the reaction: H2(g)+X2(g)⇌2HX(g) where X2 can be Cl2, Br2, or I2. Reactant/Product ΔH∘f(kJ/mol) ΔS∘f(J/mol⋅K) H2(g) 0 130.7 Cl2(g) 0 223.1 HCl(g) -92.3 186.9 Br2(g) 30.9 245.5 HBr(g) -36.3 198.7 I2(g) 62.42 260.69 HI(g) 26.5 206.6 Calculate ΔH∘ for the reaction between hydrogen and Br2.

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14,16 18 reacts with group

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it's c. elements are placed in rows based on how may valencies electrons have.

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For cyclohexane compounds drawn in a chair conformation: -axial bonds are vertical -equatorial bonds are parallel to two bonds within the ring. thus, as i assume the chair conformation is drawn: -the x group is in an axial position, as are the five other vertical bonds. -three axial bonds are on the top face of the ring -the other three axial bonds are on the bottom face the position of the second substituent on each ring carbon is equatorial. gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other. drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1. click this link and watch some academic videos that may you more understand the topic

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assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.

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H2 reacts with the halogens (X2) according to the reaction: H2(g)+X2(g)⇌2HX(g) where X2 can be Cl2,...

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