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Mr. Thorton the science teacher was explaining the difference betweent potential energy and kinetic energy. He compared the difference to a wind up toy. He said, "kinetic energy is like a wind up toy that is let go and moving but potential energy is when the wind up to is wound up but is not released yet." What misconception may come from this analogy?

Question 2 options:

A. Any object can have kinetic energy
B. All objects at rest can have some potential energy
C. potential energy can change into kinetic energy
D. An object with kinetic energy can only move for a certain amount of time and then it stops.

The correct answer is D

"An object with kinetic energy can only move for certain amount of time and then it stops."

Explanation:

I took the test, I got this question wrong because I listened to the other answer, (Sorry Kwameplayz) but thankfully I had 3 attempts. I did it again and this was the correct answer.

Hope I could help! :)

part 1: the half-life of the element is 22 years.

part 2: it will take 132.02 year for the sample to decay from 308.0 g to 4.8125 g.

explanation:

part 1: there are two ways to determine the half life time.

first way: the half life time can be determined directly from its definition as it is the time required for the sample to decay to its half concentration.

from the data the initial concentration was 45.0 g and decayed to its half value (22.5 g) in 22.0 years.

second way: the radio active decay is considered first order reaction so we can use the laws of first order reactions.

k = (1/t) ln (a/a-x), where k is the rate constant of the reaction,

t is the time of the reaction

a is the initial concentration of the reactant

a-x is the remaining concentration at time (t)

a = 45.0 g the initial concentration at t = 0 year.

at t = 22 year, a-x = 22.5 g

then k = (1/22 year) ln (45.0 g/ 22.5 g) = 0.0315 year-1.

the half-life time (t1/2) = ln 2/ k = 0.693/ k =0.693/ 0.0315 = 22 years.

part 2:

using the same law k = (1/t) ln (a/a-x),

using the given data; a = 308.0 g and a-x = 4.8125 g and the calculated k from the part 1 (k = 0.0315 year-1)

t = (1/k) ln (a/a-x) = (1/0.0315) ln (308.0/ 4.8125) = 132.02 years