What is the molarity of H2SO3 if 250 mL of the acid was used to neutralize 200 mL of 1.5 M solution of Mg(OH)2?

Molarity of is 1.2 M.

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

where,

are the n-factor, molarity and volume of acid which is

are the n-factor, molarity and volume of base which is

We are given:

Putting values in above equation, we get:

Thus molarity of is 1.2 M if 250 mL of the acid was used to neutralize 200 mL of 1.5 M solution of

there all right good

explanation: