The specific heat of copper is 0.4 J/g^ *C If a sample of copper absorbs 480J of energy and its temperature changes from 20.0 ^* c to 60.0 ^ * C what mass of copper was heated?

The mass of copper that was heated is 30 g

Explanation:

The formula for the heat supplied, ΔH is;

ΔH = m·c·Δt

Where:

ΔH = Heat supplied = 480 J

m = Mass of the copper sample = Required

c = Specific heat capacity of copper = 0.4 J/(g·°C)

Δt = Change in temperature = T₂ - T₁ = 60° - 20° = 40°C

T₁ = Initial temperature = 20°C

T₂ = Final temperature = 60°C

Therefore, plugging the values, we have;

480 = m×0.4×40

m = 480/(0.4 × 40) = 30 g

The mass of copper that was heated = 30 g.

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i'm pretty sure its b i might be wrong though!