A 3.88 mol sample of gas has a temperature of 28°C and a pressure of 885 torr. What is its volume?

V = 82.31L

Explanation:

Number of moles (n) = 3.88 moles

Temperature (T) = 28.0°C = (28.0 + 237.15)k = 301.15K

P = 885torr = 1.164atm (convert pressure in torr to atm)

1 atm = 760torr

x atm = 885 torr

X = (885 * 1) / 760

P = 1.164atm.

Volume (V) = ?

R = 0.082J/mol.K

From ideal gas equation,

PV = nRT

P = pressure

V = volume of the gas

n = number of moles

R = idealgas constant

T = temperature

PV = nRT

V = nRT/ P

V = (3.88 * 0.082 * 301.15) / 1.164

V= 82.31L

The volume of the gas is 82.31L

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