2NaN3 ---> 2Na + 3N2
An unknown amount of sodium azide (NaN3) reacts and produces 0.033 moles of nitrogen gas. What mass of sodium metal is produced?

g

Rounded to 3 significant figures

0.51g

Explanation:

2NaN3 ---> 2Na + 3N2

From the balanced reaction equation, we can be able to forge ahead in solving the question.

We can see from the equation that 2 moles of sodium azide yields 3 moles of nitrogen gas

x moles of sodium azide yields 0.033 moles of nitrogen gas

x= 0.033×2/3= 0.022 moles of sodium azide.

From the reaction equation, we can also see that;

2 moles of sodium azide yielded 2 moles of sodium

0.022 moles of sodium azide will yield 0.022 × 2/2= 0.022 moles of sodium metal.

Molar mass of sodium metal= 23 gmol-1

Mass of sodium produced= 0.022 moles of sodium metal × 23 gmol-1= 0.506g

0.506g

Explanation:

Step 1:

The balanced equation for the reaction. This given below:

2NaN3 —> 2Na + 3N2

Step 2:

Determination of the number of mole of sodium azide (NaN3) that reacted to produce 0.033 mole of nitrogen gas (N2).

This is illustrated below:

From the balanced equation above,

2 moles of Na3N reacted to produce 3 moles of N2.

Therefore, Xmol of Na3N will react to produce 0.033 mole of N2 i.e

Xmol of Na3N = (2 x 0.033)/3

Xmol of Na3N = 0.022 mole.

Therefore, 0.022 mole of Na3N reacted.

Step 3:

Determination of the number of mole of Na produced from the reaction. This is illustrated below:

From the balanced equation above,

2 moles of Na3N reacted to produce 2 moles of Na.

Therefore, 0.022 mole Na3N will also produce 0.022 mole of Na.

Step 4:

Conversion of 0.022 mole of Na to grams. This is illustrated below:

Number of mole Na = 0.022 mole

Molar Mass of Na = 23g/mol

Mass of Na =.?

Mass = number of mole x molar Mass

Mass of Na = 0.022 x 23

Mass of Na = 0.506g

Therefore, 0.506g of sodium (Na) is produced

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