Write the net ionic equation of aluminum hydroxide and nitric acid. al(oh)3(s)

2Al(OH)₃ (s) + 6H⁺ (aq) + 6NO₃⁻ (aq) → 2Al³⁺ + 6NO₃⁻ + 6H₂O (l)

Explanation:

1) Start understanding the nature of the reactants, the kind of reaction that occurs, and the nature of the products:

i) word equation:

aluminium hydroxide + nitric acid → aluminum nitrate + water

ii) molecular equation, including the phases:

2Al(OH)₃ (s) + 6HNO₃ (aq) → 2Al(NO₃)₃ (aq) + 6H₂O (l)

iii) It is a neutralization reaction between an amphoteric compound, which is acting as a base, soluble in acid, and an acid in a aqueous solution, leading to the formation of a soluble salt and water in a double replacement reaction.

2) Separate the ionic aqueous compounds into its ions

i) Reactant side:

6HNO₃ (aq) = 6H⁺ (aq) + 6NO₃⁻ (aq)

Al(OH)₃ (s) remains unchanged because it is in solid form

ii) Product side

2Al(NO₃)₃ (aq) = 2Al³⁺ + 6NO₃⁻

H₂O (l) remains unchanged because it is in liquid form.

3) Write both sides, i.e. the complete reaction in the ionic form:

2Al(OH)₃ (s) + 6H⁺ (aq) + 6NO₃⁻ (aq) → 2Al³⁺ + 6NO₃⁻ + 6H₂O (l)

4) Spectator ions

Observe that there are not spectator ions. All the ions are participating.

Hence, the net ionic equation is the same complete ionic equation.

the temperature of the gas, in k, not celsius.