The following data were collected at the endpoint of a titration performed to find the molarity of an HCl solution.

Volume of acid (HCl) used = 14.4 ml

Volume of base (NaOH) used = 22.4 ml

Molarity of standard base (NaOH) = 0.20 M

What is the molarity of the acid solution?

A) 1.6 M

B) 0.64 M

C) 0.31 M

D) 0.13 M

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of c is as shown here in the image.

a  solution  is always transparent, light passes through with no scattering from solute particles which are molecule in size. the  solution  is homogeneous and does not settle out. a colloid is intermediate between asolution  and a  suspension. while asuspension  will separate out a colloid will not.

the answer is 0.8m.

by: nicholas