The molecule carbon disulfide (CS2) is nonpolar and has only London dispersion forces between the molecules. Carbon tetrachloride (CCl4) is also nonpolar but is made of larger molecules that are more strongly affected by London dispersion forces. Based on this information, CS2 likely has a- melting point and a- vapor pressure when compared with CCl4.

Lower, higher (Plato)

Explanations:- Since both the molecules are non polar, the forces of attraction for carbon tetrachloride are comparatively stronger as it's a bigger molecule. We know that, stronger are the forces of attraction, higher is the melting point as more heat is required to break the bonds.

Stronger are the forces of attraction, lower is the vapor pressure as the molecules are more tightly bonded and less molecules goes to the gas phase.

So, melting point of carbon tetrachloride is higher but it's vapor pressure is lower as compared to carbon disulfide

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.