How many grams of ammonia gas can be formed from 54.1 g of hydrogen gas

304.19 g

Explanation:

M(H2) = 2*1 = 2 g/mol

54.1 g H2 * 1 mol H2/2gH2 = 27.05 mol H2        

                                   3H2 + N2 > 2NH3

from reaction             3 mol                  2 mol

given                   27.05 mol                 x mol

x = 27.05*2/3 = 18.03 mol NH3

M(NH3) = 14 +3*1 = 17 g/mol

18.03 mol NH3 * 17 g NH3/ 1 mol NH3 ≈ 307 g

Closeet answer is 304.19 g.

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