A 50.00 g sample of an unknown metal is heated
to 45.00°C. It is then placed in a coffee-cup
calorimeter filled with water. The calorimeter and
the water have a combined mass of 250.0 g and
an overall specific heat of 1.035 cal/g.°C. The
initial temperature of the calorimeter is 10.00°C.
The system reaches a final temperature of 11.08°C
when the metal is added. what is the specific heat?

1) according to the law of conservation of mass ,in all chemical reactions total mass is unchanged

The answer is 5 10 15

Use the universal gas law formula: pv = nrt now, the key word in this problem is stp, so at stp, temperature will always be 0 degrees celsius and pressure will always be 1.0 atm or 760 torr. given something is at stp, we already know the two variables pressure and temperature. the other thing we can find with the given information is moles. to find moles, just divide grams by molar mass of the element. 16.0g / 2(16.00)g/mol = 0.5 moles plug the values in to the equation pv = nrt (1.0 atm)( x ) = (0.5 )(0+273=273k) the r value is just a constant for when we use atm, liters, moles and kelvin. i'm assuming you want your answer in liters, but if you dont just move the decimal 3 to the right in your final answer. so when plugging these numbers in to your calculator and trying to find x, you get 11.20665 liters using significant figures the answer is 11.2 liters

Sro would be  your answer