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Chemistry, 05.05.2020 12:00 cicilee49

N2(g) + 3H2(g) —
2NH3(g)
How many moles of nitrogen would react with excess hydrogen to produce 520 mL of ammonia?
0.0116 mol
0.012 mol
0.0232 mol
0.024 mol

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Answers: 1

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N2(g) + 3H2(g) —
2NH3(g)
How many moles of nitrogen would react with excess hydrogen to...
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