The reaction of benzene, C6H6, with excess HNO3 resulted in 1.3 g
of H20. If the percentage yield was 15% what was the theoretical
yield?
C6H6 + HNO3 - C6H5NO2 + H20
Molar Mass: C6H6 = 78 g/mol; HNO3 = 63 g/mol; C6H5NO2 =123
g/
mol; H20 =18 g/mol