How many moles of ammonia would be required to react exactly with 0.470 moles of cooper (ll) oxide in the following chemical reaction? 2 NH₃ (g) + 3 CuO (s) → 3 Cu (s) + N₂ (g) + 3H₂O (g)

0.313 mole of NH3

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2NH3(g) + 3CuO(s) → 3Cu(s) + N2(g) + 3H2O(g)

The number of mole of ammonia (NH3) required to react with 0.470 mole of copper(ll) oxide (CuO) can be obtained as follow:

From the balanced equation above,

2 moles of NH3 reacted with 3 moles of CuO.

Therefore, Xmol of NH3 will react with 0.470 mole of CuO i.e

Xmol of NH3 = (2 x 0.470) /3

Xmol of NH3 = 0.313 mole.

Therefore, 0.313 mole of NH3 is needed for the reaction

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