If 7.0 g of copper were heated from 11.0 Celsius to 43 Celsius in a Coffee cup calorimeter How much heat was absorbed by the copper?

Where are the questions

While unproven, it uses facts to support part of a conclusion. it is still factual and has predictive power, however.

Heat capacity = mcδtheat capacity = 2.676×10^3 j ..the heat capacity given is for 7.00 g of kcn,potassium cyanide which is equal to 0. mole of mole = mass  ÷ mr of kcn is 7  ÷ 65 =0.therefore: 0. of kcn liberates 2.676×10^3 j of heat1 mole   (2.676×10^3    ÷  0.107 )  × 1 =do the calculation to obtain 25009 j = 25kj

The first one is the one that violate the law