9)

I have an unknown volume of gas held at a temperature of

115 Kin á container with a pressure of 60 atm. If by

increasing the temperature to 225 K and decreasing the

pressure to 30 atm causes the volume of the gas to be 29

liters, how many liters of gas did I start with?

Answer : The volume of gas will be, 113.5 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

where,

= initial pressure of gas = 60 atm

= final pressure of gas = 30 atm

= initial volume of gas = 29 L

= final volume of gas = ?

= initial temperature of gas = 115 K

= final temperature of gas = 225 K

Now put all the given values in the above equation, we get:

Therefore, the volume of gas will be, 113.5 L

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