The overall reaction in the lead storage battery is

Pb(s) + PbO2(s) + 2H1(aq) + 2HSO42(aq) > 2PbSO4(s) + 2H2O(l)

Calculate % at 258C for this battery when [H2SO4] 5 4.5 M; that is, [H1] 5 [HSO42] 5 4.5 M. At 258C, %8 5 2.04 V for the lead storage battery.

Complete Question

The overall reaction in the lead storage battery is

Calculate  E at 25°C for this battery when [H2SO4] = 5.0 M; that is, [H + ] = [HSO4− ] = 5.0 M. At 25°C,  E° = 2.04 V for the lead storage battery.

The  voltage of the cell is  

Explanation:

 From the question we are told that

          The original voltage of the battery is

           The concentration of  [H2SO4] = 5.0 M

            The concentration of  [H + ] = [HSO4− ] = 5.0 M

At equilibrium

                   The reaction quotient is  

Pb(s), Pb(s), 2 H2O(l),2 PbSO4(s) are excluded from the reaction above because they are solid and liquid thus there concentration does not change

So the potential for the battery cell is mathematically evaluated as

2.12 V

Explanation:

see attached file for the detailed step by step solution of the given problem.

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.

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