Calculate the molarity of Na+ ions in a 100 ml solution containing 0.46 g Na3PO4

0.084 M

Explanation:

molar mass of Na3PO4 = 3*23 + 31 + 4*16 = 164 g/mol

moles of Na3PO4 = mass / molar mass = 0.46/164 = 0.0028 mol

There are 3 moles of Na+ in 1 mol of Na3PO4, so there are 3*0.0028 = 0.0084 moles of Na+ in the solution

Molarity is defined as:

M = moles of solute/litre of solution

100 ml are equivalent to 0.1 L

Therefore:

M of Na+ = 0.0084/0.1 = 0.084 M

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error