Consider the following reaction:
I2O5(s) + 5 CO (g) → I2(s) + 5 CO2(g)

Which of the following correctly characterizes this reaction?
The oxidation number of iodine in the reactants is +5.
CO is oxidized.
I2O5 is the oxidizing agent.

The three statements are true

Explanation:

For the reaction:

I₂O₅(s) + 5CO(g) → I₂(s) + 5CO₂(g)

State oxidation of iodine in I₂O₅ is:

5 O²⁻ = 10⁻

As you have 2 I and the molecule has no charge, oxidation state of I is +5.

The carbon in CO has an oxidation state of +2 and in CO₂ is +4. That means the carbon is oxidized

An oxidizing agent is a substance that produce the oxidation of the agent that reacts with this one. CO is oxidized because of I₂O₅ is producing its oxidation being the oxidizing agent

Thus, the three statements are true.

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